-16x^2+33x+15=0

Solution for -16x^2+33x+15=0 equation:

-16x^2+33x+15=0

a = -16; b = 33; c = +15;
Δ = b2-4ac
Δ = 332-4·(-16)·15
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{2049}}{2*-16}=\frac{-33-\sqrt{2049}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{2049}}{2*-16}=\frac{-33+\sqrt{2049}}{-32}
$